Question

K.Gunner Stoichiometry, Balance equations, Types of reaction An aqueous solution of Potassium chlorate reacts with an aqueous solution of Iron Ill Carbonate to produce an aqueous salt solution and a precipitated salt containing the Iron Iillon, as products. 1) Predict the products that will be produced and Write the correct formulas for each. 2) Write the entire Chemical equation both products and reactants, include in your equation the correct formulas for each and the proper phases associated with each formula. 3) Write the Name of the reaction mechanism. (Type of reaction) 4) Write the complete equation and Balance the chemical equation 5) Based on the following information and the balanced equation: Calculate the quantity of grams of the precipitated salt that would actually be produced when starting with 65.7 grams of Potassium chlorate reacting with excess grams of Iron Ill carbonate. (show all factor label work)

Answer 1

a)

Products of reaction are Iron (III) chlorate (Fe(ClO₃)₃) and Potassium carbonate (K₂CO₃)                   

b)

KClO₃ + Fe₂(CO₃)₃ --> Fe(ClO₃)₃ (ppt.) + K₂CO₃ (aq)

                              Iron (III) chlorate + Potassium carbonate

c)

This is a double displacement reaction.

d)

6 KClO₃ + Fe₂(CO₃)₃ --> 2 Fe(ClO₃)₃ + 3 K₂CO₃

e)

Molar mass of KClO₃ = 122.6 g/mol

Molar mass of Fe(ClO₃)₃ = 306.2 g/mol

Moles of KClO₃ added = 65.7 g / 122.6 g/mol

= 0.536

Moles of Fe(ClO₃)₃ formed = 0.536 * 2/6 = 0.179

Mass of Fe(ClO₃)₃ formed = 0.179 mol * 306.2 g/mol

= 54.7 g