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Aluminum ion in solution reacts with water to form aqueous hexaaguaaluminum ()ion. Write this reaction below, remember phases

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Answer #1

The formation of hexaaquaaluminium(III) ion can be represented as follows

Al3+ (aq) + 6 H2O (l) phppzgumP.png[Al(H2O)6]3+ (aq)

Addition of ammonia base into the water results in the availability of large amounts of OH- ions, Both Al(III) ions and Fe(III) ions present in the water reacts with this hydroxide ions (OH-) to form their respective hydroxides.

Al3+ (aq) + 3 OH- (aq) phppzgumP.pngAl(OH)3 (s)

Fe3+ (aq) + 3 OH- (aq) phppzgumP.pngFe(OH)3 (s)

Group D metal ion Copper reacts in ammonia solution to form its tetraamine complex in the following way

Cu2+ (aq) + 4 NH3 (aq) phppzgumP.png[Cu(NH3)4]2+ (aq)

After the addition of sodium hydroxide, the precipitate aluminium hydroxide reacts with the hydroxide ions to form aqueous tetrahydroxoaluminate ion

Al(OH)3 (s) + OH- (aq) phppzgumP.png[Al(OH)4]- (aq)

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