mass of NaOH = 0.157 g
Explanation
concentration AlCl3 = 0.131 M
volume AlCl3 = 10.0 mL = 0.0100 L
moles AlCl3 = (concentration AlCl3) * (volume AlCl3 in Liter)
moles AlCl3 = (0.131 M) * (0.0100 L)
moles AlCl3 = 0.00131 mol
moles Al3+ = moles AlCl3
moles Al3+ = 0.00131 mol
Al3+ (aq) + 3 OH- (aq) Al(OH)3 (s)
moles OH- = 3 * (moles Al3+)
moles OH- = 3 * (0.00131 mol)
moles OH- = 0.00393 mol
moles NaOH = moles OH-
moles NaOH = 0.00393 mol
mass NaOH = (moles NaOH) * (molar mass NaOH)
mass NaOH = (0.00393 mol) * (40.0 g/mol)
mass NaOH = 0.1572 g
NONTON Aluminum ions may be precipitated from aqueous solution by the addition of hydroxide ion, forming...
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