the copper (ii) ion reacts with phosphate ion to form an insoluable ionic compound...Lap= 1.40x10..-37.... the...
the copper (ii) ion reacts with phosphate ion to form
an insoluable ionic compound...Lap= 1.40x10..-37....
the copper (ii)ion also forms a complex ion with
ammonia...(Cu(NH3)4)+2...Kf=5.03×10..13
write the chemical formula that occurs between them. also make sure
you include states of matter.
Homework Answers
Reaction 1 : Cu3(PO4)2 (s)
3 Cu2+ (aq) + 2 PO43- (aq) :
Ksp = 1.40 x 10-37
Reaction 2 : Cu2+ (aq) + 4 NH3 (aq)
Cu(NH3)42+ (aq) : Kf =
5.03 x 1013
Multiply Reaction 2 by a factor of 3 and add to Reaction 1 to cancel out the 3 Cu2+ (aq) term
Overall reaction :
Cu3(PO4)2 (s) + 12
NH3 (aq)
3 Cu(NH3)42+ (aq) + 2
PO43- (aq)
overall equilibrium constant, K = (Ksp) * (Kf)3
K = (1.40 x 10-37) * (5.03 x 1013)3
K = (1.40 x 10-37) * (1.27 x 1041)
K = 1.78 x 104
Add Answer to:
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