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A volume of 50.0 mL of 0.0900 M CaCl2 reacts with excesss sodium carbonate to give...

A volume of 50.0 mL of 0.0900 M CaCl2 reacts with excesss sodium carbonate to give 0.366 g of calcium carbonate precipitate. What is the percent yield?

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Answer #1

Cacl + Na CO₂ CO₂ + 2 race. Imole excess Imole amoles 0.0045 mole 0.0045 mole Concentration of Carl = 0.09 M So, IL contain:0.45g is the the critical yield. Actual yield 0.366 g 0.366 x 100 рела море уча ва к во percento 0.45 = 181.33%

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