How many d electrons are in the valence shell of the Cr + 4 cation? How...
How many d electrons are in the valence shell of the Cr + 4 cation? How many unpaired electron spins?
Homework Answers
Number of electron in Cr = 24
Electronic configuration is: 1s2 2s2 2p6 3s2 3p6 3d5 4s1
Explanation: Half filled orbital are more stable.
so instead of 4s2 3d4, we go for 4s1 3d5 where both orbitals are
half filled
Since charge on Cr is +4
So, we need to remove 4 electrons
Electrons are always removed from highest number orbital
Removing 1 electron from 4s
Removing 3 electron from 3d
Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d2
1)
There are 3 d electrons
Answer: 2
2)
Both of these electrons in d orbitals will be unpaired.
Because pairing doesn’t take place until all 5 of d orbitals are
singly occupied.
Answer: 2
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