If 14.4 moles of Cu and 17.4 moles of HNO3 are allowed to react, what is...
If 14.4 moles of Cu and 17.4 moles of HNO3 are allowed to react, what is the maximum number of moles of NO that can be produced?
3 Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
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If 14.4 moles of Cu and 17.4 moles of HNO3 are
allowed to react, what is...
If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the re...
If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion? 3 Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
1. When 15.4 g of aluminum (26.98 g/mol) reacts with 14.8 g of oxygen gas (32.00...
1. When 15.4 g of aluminum (26.98 g/mol) reacts with 14.8 g of oxygen gas (32.00 g/mol), what is the maximum mass (in grams) of aluminum oxide (101.96 g/mol) that can be produced? 4 Al(s) + 3 O2(g) → 2 Al2O3(s) 2. If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion? Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O...
Cu(s) + 8HNO3(aq) → 2NO(g) + 3Cu(NO3)2(aq) + 4H2O(l) If 15 g of copper metal was...
Cu(s) + 8HNO3(aq) → 2NO(g) + 3Cu(NO3)2(aq) + 4H2O(l) If 15 g of copper metal was added to an aqueous solution containing 6.0 moles of HNO3, how many moles of NO(g) would be produced, assuming a 75 % yield.
. AT&T 8:47 PM 67% Exit In the reaction 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 4H2O(l)...
. AT&T 8:47 PM 67% Exit In the reaction 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 4H2O(l) + 2NO(g) 6.3 g of Cu and 100.0 mL of 1.0 M HNO3 are combined. Which of the following statements is true? O 0.080 mol H2O is produced O Cu and HNO3 are present in stoichiometric amounts; neither is in excess. O Cu is the limiting reagent, and 0.062 mol HNO3 does not react. O HNO3 is the limiting reagent, and 0.062 mol Cu...
Question 3 In a laboratory experiment, 23.4 g of Cu were reacted with 141.9 g of...
Question 3 In a laboratory experiment, 23.4 g of Cu were reacted with 141.9 g of HNO, 3Cu + 8HNO, — 3Cu(NO3)2 + 4H20 + 2NO (a) How many grams of Cu(NO3)2 can be theoretically produced? g Cu(NO3)2 Use correct number of significant digits, the tolerance is +/-2% (b) How many grams of the excess reactant remain? Excess reactant: Edit Grams remaining Use correct number ondant as the verge 5 8 USE Lunet me Ur SIYmeant uys, te toverance is...
What mass of Cu metal is required to react with 6.8 drops of 16M HNO3? Assume...
What mass of Cu metal is required to react with 6.8 drops of 16M HNO3? Assume 20 drops = 1 mL. Cu (MM 63.54 g/mol), (16M = 16 mol/L) Cu(s)+4HNO3(aq) a Cu(NO3)2(aq) + 2NO2(g)+ 2H20(0) Hint x drops HNO3 X Cu XLX mol X drops mL mol mol Give answer to 2 significant figures. Do not use scientific notation. After the number, include one space and then the unit, g. Do calculation all at once, round off at the end.
Question 17 (4 points) ✓ Saved 50.0 g Cu are combined with 50.0 g of HNO3...
Question 17 (4 points) ✓ Saved 50.0 g Cu are combined with 50.0 g of HNO3 according to the reaction: 3 Cu + 8 HNO3 +3 Cu(NO3)2 + 2 NO + 4H20. Which reagent is limiting (Blank #1) and how many grams of NO are produced (Blank #2)? Enter the number in the second blank with 3 significant figures and without units.
Show all work neatly please l mol Cu was added to a solution containing 4 moles...
Show all work neatly please
l mol Cu was added to a solution containing 4 moles of HNO_3 which react according to the following Chemical equation 3Cu_(s) + 8HNO_3(aq) rightarrow 3Cu(NO_3)_2(aq) + 4H_2O_(l) + 2NO_(g) What is the limiting reactant (LR) and how many moles of No could be produced? LR = Cu, 1.5 moles of No. LR = 4HO_3, 2 moles of No. LR = C4, 213 moles of No. LR = HNO_3, 1/2 moles of No. LR =...
need help balancing the 1st equation then name what type of reaction is occurring for each equation A HNO3(aq) + Cu(...
need help balancing the 1st equation
then name what type of reaction is occurring for each
equation
A HNO3(aq) + Cu(s) + O2(g) - Cu(NO3)2(aq) + 4H2O(l) +BANO2(g) Cu(NO3)2(aq) + 2 NaOH(aq) - Cu(OH)2(s) +2 NaNO3(aq) rxn. 2 Cu(OH)2(s) - CuO(s) + H2O(l) rxn. 3 rxn. 4 Cuo(s) + H2SO4(aq) CuSO.(aq) + Zn(s) — CuSO4(aq) + H2O(l) + ZnSO4(aq) + Cu(s) rxn. 5
Copper reacts with nitric acid via the following equation: 3 Cu(s) + 8 HNO3(aq) → 3...
Copper reacts with nitric acid via the following equation: 3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H2O(ℓ) What mass of NO(g) can be formed when 20.7 g of Cu reacts with 50.0 g HNO3? g NO
. AT&T 8:47 PM 67% Exit In the reaction 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 4H2O(l) + 2NO(g) 6.3 g of Cu and 100.0 mL of 1.0 M HNO3 are combined. Which of the following statements is true? O 0.080 mol H2O is produced O Cu and HNO3 are present in stoichiometric amounts; neither is in excess. O Cu is the limiting reagent, and 0.062 mol HNO3 does not react. O HNO3 is the limiting reagent, and 0.062 mol Cu...
Question 3 In a laboratory experiment, 23.4 g of Cu were reacted with 141.9 g of HNO, 3Cu + 8HNO, — 3Cu(NO3)2 + 4H20 + 2NO (a) How many grams of Cu(NO3)2 can be theoretically produced? g Cu(NO3)2 Use correct number of significant digits, the tolerance is +/-2% (b) How many grams of the excess reactant remain? Excess reactant: Edit Grams remaining Use correct number ondant as the verge 5 8 USE Lunet me Ur SIYmeant uys, te toverance is...
What mass of Cu metal is required to react with 6.8 drops of 16M HNO3? Assume 20 drops = 1 mL. Cu (MM 63.54 g/mol), (16M = 16 mol/L) Cu(s)+4HNO3(aq) a Cu(NO3)2(aq) + 2NO2(g)+ 2H20(0) Hint x drops HNO3 X Cu XLX mol X drops mL mol mol Give answer to 2 significant figures. Do not use scientific notation. After the number, include one space and then the unit, g. Do calculation all at once, round off at the end.
Question 17 (4 points) ✓ Saved 50.0 g Cu are combined with 50.0 g of HNO3 according to the reaction: 3 Cu + 8 HNO3 +3 Cu(NO3)2 + 2 NO + 4H20. Which reagent is limiting (Blank #1) and how many grams of NO are produced (Blank #2)? Enter the number in the second blank with 3 significant figures and without units.
Show all work neatly please
l mol Cu was added to a solution containing 4 moles of HNO_3 which react according to the following Chemical equation 3Cu_(s) + 8HNO_3(aq) rightarrow 3Cu(NO_3)_2(aq) + 4H_2O_(l) + 2NO_(g) What is the limiting reactant (LR) and how many moles of No could be produced? LR = Cu, 1.5 moles of No. LR = 4HO_3, 2 moles of No. LR = C4, 213 moles of No. LR = HNO_3, 1/2 moles of No. LR =...
need help balancing the 1st equation
then name what type of reaction is occurring for each
equation
A HNO3(aq) + Cu(s) + O2(g) - Cu(NO3)2(aq) + 4H2O(l) +BANO2(g) Cu(NO3)2(aq) + 2 NaOH(aq) - Cu(OH)2(s) +2 NaNO3(aq) rxn. 2 Cu(OH)2(s) - CuO(s) + H2O(l) rxn. 3 rxn. 4 Cuo(s) + H2SO4(aq) CuSO.(aq) + Zn(s) — CuSO4(aq) + H2O(l) + ZnSO4(aq) + Cu(s) rxn. 5
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