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If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the re...

If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion?

3 Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

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3 ou + 8 HNO 3 3 moles of cel 19mole of Cu - 3 CU (NO3 + 2N0 + 4H₂O react with 8 moles of HNO 3 react with moles @ HNO3 = 8 mplease rate

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