25. How many moles of excess reactant remain after the complete reaction of 18 mol of sulfur (S8) with 31.2 mole of oxygen gas (O2).
S8 + 8 O2 → 8 SO2
S8 + 8 O2 → 8 SO2
Here, 1 mole of sulfur reacts with 8 mole of oxygen to form 8 moles of SO2.
31.2 mole of oxygen can react with 3.9 mole of sulfur.
no of moles of excess reactant = 18 - 3.9 = 14.1 mole of sulfur
25. How many moles of excess reactant remain after the complete reaction of 18 mol of...
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