1.82 m moves at constant velocty V (23.8 m/s) through a uniform magnetic field 8 (34.9...
Chapter 28, Problem 015 Your answer is partially correct. Try again. In the figure, a conducting rectangular body of dimensions dr-5.48 m, dy-4.09 m, and dr·1.98 m moves at constant velocity - (12.2 m/s) through a uniform magnetic field 8 (40.8 mT) . (a) What is the resulting electric field within the body, in unit-vector notation? (b) What is the resulting potential difference across the body? k ) Units (a) Number N/C-m Units (b) Number Click if you would like...
In the figure, a conducting rectangular body of dimensions d - 5.05 m, dy - 3,42 m, and d, - 2.05 m moves at constant velocity 7 - (19.4 m/s) through a uniform magnetic field B = (31.1 m j. (a) What is the resulting electric field within the body, in unit-vector notation? (b) What is the resulting potential difference across the body? (a) number c a as unit (b) Number
An electron moves through a uniform electric field vector E = (2.40î + 5.70?) V/m and a uniform magnetic field vector B = 0.400k T. Determine the acceleration of the electron when it has a velocity vector v = 6.0î m/s. ax= ay= az=
An electron travels through the uniform magnetic field of field strength B = (2.5 i + 3.5 j ) mT and electric field of field strength 4.00 I V/M . If the electron is moving with the velocity v= (1500 j + 2000 k)m/s. Calculate the net force acting on the electron in terms of unit vector notation.
An electron moves through a uniform electric field vector E = (2.30î + 4.10ĵ) V/m and a uniform magnetic field vector B = 0.400k T. Determine the acceleration of the electron when it has a velocity vector v = 6.0î m/s. ax = _____ m/s2 ay = _____m/s2 az = ______m/s2
(10) A rectangular conducting slab with dimensions dx = 7.00 m, dy = 3.00 m, and dz = 2.00 m (not drawn to scale in the Figure), is moving through a uniform magnetic field B = 40.0 I mt with a velocity v = 20.0 i m/s in the x direction. What is the hall potential difference (in Volts)? 00 m (not drawn to scale in the Figures, 1. 2.4 2. 00 3. O 1.6 4. O 16.2 5. 0.027...
Problem 1: An electron travels through the uniform magnetic field of field strength B = (2.5 i +3.5i) mt and electric field of field strength 4.00 IV/M. If the electron is moving with the velocity v= (1500 j + 2000 k)m/s. Calculate the net force acting on the electron in terms of unit vector notation.
A particle with a charge of 3.0 C moves through a uniform magnietic field. At one instant the velocity of the particle is ?⃑ = (3.0?̂+ 4.0?̂− 6.0?̂) m/s and the magnetic force on the particle is ?⃑ ? = (−8.0?̂+ 3.0?̂+ 2.0?̂) N. In unit-vector notation, determine the magnetic field B.
An electron moves through a uniform magnetic field given by B =
Bxi+(3.74Bx)j. At a particular instant, the electron has velocity V
=(2.88i+4.37j)m/s and the magnetic force acting on it is
(2.74x10^-19)k N. Find Bx
An electron moves through a uniform magnetic field given by B 3.74 B . At a articular instant, the electron has velocit y 2.88 , -37 m/s and the magnetic orce acting on t is 7 ·r Linda Number Units
A proton moves through a region containing a uniform electric field given by = 30.0 ĵ V/m and a uniform magnetic field = (0.200 î + 0.300 ĵ + 0.400 ) T. Determine the acceleration of the proton when it has a velocity = 230 î m/s. could you also explain in detail the vector addition process?