Can you please help me understand this question, I have a test soon and I don't quite know how to use the energy equation.
(a) Intial potential energy
Ei = m*g*(L/2) + M*g*(L+R)
Ei = (0.4*9.8*0.15) + (4*9.8*0.5) = 20.188 J
Final kinetic energy at the bottom
Ef = (1/2)*(Istick + Idisk)*w^2
Istick = (1/2)*m*L^2 = (1/2)*0.4*0.3^2 = 0.018 kg m^2
Idisk = (1/2)*M*R^2 + M*(R+L)^2
Idisk = (1/2)*4*0.2^2 + (4*0.5^2) = 1.08 kg m^2
from energy conservation Ef = Ei
(1/2)*(0.018 + 1.08)*w^2 = 20.188
angular speed w = 6.06 rad/s
linear speed v = w*(R+L) = 6.06 *0.5 = 3.03 m/s
(b) net torque = I*alpha
alpha = angular acceleration = a/(R+L)
m*g*L/2 + M*g*(R+L) = I*a/(R+L)
(0.4*9.81*0.15) + (4*9.81*0.5) = (0.018+1.08)*a/0.5
a = 9.19 m/s^2
(c) acceleration a = v^2/(R+L) = 3.03^2/0.5 = 18.36 m/s^2
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Can you please help me understand this question, I have a test soon and I don't...
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