Question

PHY101 Worksheet CO1b (1) - Word Table Tools - 0 x & Share Design Layout References Mailings Review View Help Design Layout _Tell me what you want to do 50- File Home Insert % Cut EB Copy Paste . Format Painter Clipboard F AL 1 - Аавьссос АаВЬСcD Аавьссос Аавьс Аавьссс Аав Аавьсср 1 Normal Subtitle 11 No Spac... Heading 1 Heading 2 Title Subtle Em... << > Calibri (Body V 11 VA A Aa A E 7 BIU - abe x, x* Aay - A 33 Font Go Paragraph T X T .1.1.2.1.3 | .4 | .5 | .6 | .7 Answer the following on the space provided: Find - ac Replace Select Editing Styles 15 | | .8 | 9 · 10 | 11 | 12 | 13 | 14 | 16 | 17 | 18 | 19 | 20 A body is projected up a 250 plane with an initial velocity of The block in the figure has a velocity of 10 m /sec. 12 m/s. If the coefficient of kinetic friction between the Determine the coefficient of kinetic friction between the body and the plane is 0.25, determine how far the body block and the ground that is required to stop the block will move up the plane and the time required to reach after moving 90 m. the highest point (Ctrl)- 10 kg 10 kg | 19.1.8.1.7.1.6.1.5.1.4.1.3.1 - P=80 N 10 | 11 | 12 | 13 | 14 5. | Page 1 of 2 164 words & English (United States) 110% DE E- - + O 4) TENG 22/11/2019 8:46 PM 2 P E

Answer 1

N = mg casas 'sܬܓܩ Let the mass of body = m. ܒܥܥܫܓ - ܥܚܓ ܬ ܓܓܡܚܤܠܟܥܡܿܠ let the distance travelled on the plane bear . - ܠܚܬܘܘܣ ܬܩܣܛܠ ܫܘ ("ܨܒܚܬ - \ Energy lost due to friction = lng (as 25). ܠܦܘܢ 8.ܦܡ255.. - € ܕ222 - Potential energy at height he migh - mgdsins

P.E - 4.14) ind from Conservation of energy 2x127 = 4.1440 +2.22% 72 - 4.140 +2.22 (d = 16.85m] height of the body Sin25 7.0 m plane friction for time acceleration due to gravity and body a = -g Sina + Halasa) - = -9.860.42+0.22) a = – 6.33 m/s² at the top v=0 => 0 = utat t=logas

ܘܦ= ܬ ܠܐܡ ܘ ܝ _ _ long - ܡܢ - ܓ݂ܟ݂ܫܤ ܠܩܠ ܐܠ ܣ - ܘܥܡ = _ ܡܠܥܠܘܬ ܬܢܩܠ ܔܢܫܡܫܚܡܣܬܝ ܛܬܟ ܥܪܚ ܥܘܘܠܠ War - Mung (ao) (ܘܦܟ݂ܚ - ܘܤ czܢ ܘܘܘ = ܪܬܙ < 0.113] = The