Solution:
Table :
A) Number of milimoles of E- stilbine
= (mass / molar mass)
= 0.058 mg / 180.25 g mol-1
= 0.058 mg / 180.25 mg/mmol (1g/mol = 1 mg/mol)
= 0.00032 milimoles
>>> Equivalent = 1
Since, one equivalent of E-stilbene reacts with one mol of pyridinium tribromide in the reaction.
B) Pyrridinium tribromide:
Number of milimoles = Mass /Molar mass
= 100 mg / 319.82 g mol-1 = 100 mg / 319.82 mg/mmol
= 0.3126 milimoles
>> Equivalent = 1
C) Meso-stilbine dibromide:
Number of milimoles = mass/molar mass
= 0.0063 mg / 340.05 g /mol
= 0.0063 mg / 340.05 mg/mmol
= 1.85 x 10^-5 mmol
please help fill in the white boxes Section: U Date: 4 the reaction equation below. Note:...
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please help do theoretical and percent yields Ce the reaction equation below. Note: consider the equilibriugarshown on p. 42 of your lab manual. Acetic id mesb-Shibanc tribromide o Bra Pyridinium tribromide E-stilbene meso-stibene dibromide step 2 Step 2: +86:0 Stepa. 2. Complete the following table, using your actual measured amounts. Greyed-out cells do not need to be filled. E-stilbene mp bp MW vol mass (°C) (C) (g/mol) (ml) (mg) mmol equiv 122- 180.25 125 ,0560.0032,094 118 IML acetic acid (glacial)...
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