Question

Please help with filling in the white boxes & balancing the reaction. if you have time and can help with 1-3 that would be great! will rate

1. Balance the reaction equation below. 2. Complete the following table, using your actual measured amounts. Greyed-out cells do not need to be filled. mp bp (°C) MW (g/mol) d vol. (g/mL) (mL) 0.962 limL mass (mg) mmol equiv cyclohexanol 26 162 100.16 amberlyst 15 129 cyclohexene -104 83 82.15 0.811 3. Describe the appearance of your product: A clear liquid. 4. Describe the results for the permanganate tests (both of your product, and of the blank): Product tube - Added ImL ethanol and a drops of product then added a drops of permangante to get a brown color. Blank tube & Added ImL of ethanol and I drop of permangante to get a persistant purple.

Answer 1

- 0.962 z żo.0096 molee. 1. Calculation of theoretical yield and percent yield 1. One molecule of cyclohexan of Should produce one molecule of cydo herene. » One mole of cyclohed an of should product one mole of cyclohexane. For this experiment you are using ime of cyclohexanof, convert this to grams I density (d? = mass(a) d=0.962 g/me year o volume (ML) valme Reorganize the equation and solve for mark. mass (m) = density & Volume : 0.9628/m2 x IML = 0.962g Convert this mass to moles. mole . mass i. mars 20.962g - Moliwt ut mol-wt = 100. 29lmos of cyclownanos mol = 0.962g " Too-2 g/me We know Imole of Cepclonerend gives inote of cyclohexene » 0.0096 moles of cyclohex a not gives 0.0096 moles of cycloherene. Convert 0.0096 moles of cycloherene to grams 1 mol & wergut mol-wt of Gudherene :82-19/mos arol-wt mol = o-0092 moles - » wa 82.1stmas x8.0092 mol =0.75 grams 1 Theorelical yield = 0.75 grams ľ 'ofo yield = Actual weight (87100 - Theoretical field (9) you got 3-8 g of cycus herene, substitute the values you will get 7 yield. %yield a la 213.8 g x 100)% = 506% 10.759 Note your ol yield is 506% this is much higher than 100% yield possible, so you might have lot of impurities along with product

2.Potassium permanganate test: An alkene reacts with potassium permanganate to form a colorless diol. Under acid conditions the diol reacts further to form a mixture of colorless carboxylic acids or in the case of a cyclic alkene, a dicarboxylic acid. As the permanganate is consumed, the mixture loses its deep purple color. At the same time manganese dioxide, a brown precipitate, forms. If a sample decolorizes permanganate and forms a brown precipitate it can be inferred that an alkene functional group is present.

For your reaction you observed purple color of the KMnO4 is lost and brown color precipitate formed, hence you successfully made the cyclohexene. This is clear evidence that you have prepared the expected product and this is a clear conclusive test.

3. KMnO4 is used to form cis-diol from any “ene”-system (double bond) like you asked for cyclohexene. Here is the mechanism of the reaction. Here is the mechanism of such reactions.

Hy + KMnO4 OH mechanism KMnog MnO4 un 420/0 OH OH cis-diol. + KMnO4 cisodiol. он он-

cyclohexane cis diols are meso compound. A meso compound is a molecule having more than one identical stereocenter and an identical or superimposable mirror image. Therefore, a meso compound has many chiral carbon centers, but the mirror image is superimposable. A meso compound also has an internal plane of symmetry that divides the molecule into two halves. These two halves are mirror images. Hence, meso compounds are optically inactive. Hence cyclohexane diol chair conformations are enantiomers.