Question

c) 12.44 M e) 35005 c) 5.31 a) 35.07 d: 3.97 e) 39.7 9. A solution has a pH of 4.67. What is the p H of the solution? a) 5.44 M b) 6.21 M 8.52 M d) 9.33M 10. Anti log of 1.545 is: b) 4.67 d; 350.07 11. What is the log of 9.333.45? a) 3.07 c) 3.73 O. SUSM 19 12. How many liters of SSSSCH12Os contain g of CHO? a) 0.01 b) 0.013 c) 0.019 d) 0.13 13. What volume of 0.25 M HCL must be diluted to make 2.5 L of 0.0525 M HCL? b) 0.5L ) 9.73L d) 0.97L b) 3.37 e) 0.17 e) 1.75L a) 0.07L Short Answer Questions (True (a) or False (b) 14. The numbers preceding the formulas for a compound in chemical equations are referred to as the moles 15. The actual yield of a chemical reaction is calculated by multiplying its limiting reagent by the molecular weight of the product. 16. The pH of purified water (or of a neutral solution) is 7.80. 17. The reaction of 2.75 g Nz with excess Hz produces 1.77 g NH3. The percent yield of this reaction is 52.9 g. 18. Solute is the substance in which the solvent dissolves in. 19. Solvent is the substance that dissolves in a solution 20. Solution is homogeneous mixture of moles of a compound. 21. Molarity is the number of solute in a kilogram of solvent. 22. pH of a solution is the negative of the logarithm of a proton or hydronium ion. 23. Stoichiometry is the qualitative information about chemical reaction. is path length and C is concentration) is known as the 24. The following equation: A=Ex1 *C (where Beer-Lambert law. 25. Chemical Equations is shorthand used by chemists to describe a chemical change

Answer 1

4.67 pH= pou 14-p 14-4.67 9.33 -Autileg (549) - 3S. 07 (a) &ILa (4333. 45) 3.97 (d) -12 Molarity ienmas Malor mau^Voume t sel n 0.25 OS X V 0. 022 180 O 2505 CArig to correcton made

a-2 According to oldupaamitu 1. 3 0.S535 V 180.0 V .3 D.SSSS 0 013 L (b) 13 M, VI M2 V2 uhere M = Vz Volume Mobrity, 0 0S2 S x 2 S O.2S V Vi o. 0S2S x 2.S O.25 (b) 0 S25 L