Question

please include how you got ti the answer.

5. Which pall UI JU a. NaOH - NaCl 4. NHÀ - NHcl b. HCI - NHCI 6. Calculate the pH of a buffer solution that contains 0.22 M hypochlorous acid (HCIO) and 0.35M sodium hypochlorite (NaClO). [Ke=3.2 x 10-8 for hypochlorous acid] pka = -10g (3.2x10-8)= 7,49 a. 3.07 b. 3.27 C 7.30 d. 7.70 e. 7.50 pH = pka tloge = 7,49 +10g .22 = 7.28 27.3 Lollin ndded to 525 mL of 0.250 M weak acid (Ka=6.8 x 104 M). What is

Answer 1

Ka = 3.2*10^-8

pKa = - log (Ka)

= - log(3.2*10^-8)

= 7.495

use:

pH = pKa + log {[conjugate base]/[acid]}

pH = pKa + log {[ClO-]/[HClO]}

= 7.495+ log {0.35/0.22}

= 7.70

Answer: d