Question

15 In an acid-base titration, the neutralization of 25.00 mL of a solution of KOH (potassium hydroxide) of unknown concentration required the addition of 22.60 mL of 0.1532 M HNO3 (nitric acid). Calculate the molarity of the potassium hydroxide solution Place your answer in the box. Express your answer using only a number or numbers without text. Report your result in decimal notation and to the proper number of significant figures. All numbers are measured,

Answer 1

For neutralisation reaction

Number of Milli moles of base = Number of Milli moles of acid

M₁V_{​​​​1} = M_{​​​​​​2} V_{​​​​​​2}

M₁ = M_{​​​​​​2} V_{​​​​​​2}/V ₁

M _KOH​ = 0.1532 X 22.60/25

M _{KOH^{​​​​ =}} 0.13849 M.