7) Titrate 20.0 mL of HNO3 with an unknown concentration with 15.4 mL of 0.300M NaOH....

Question

Question

Answer 1

Answer #1

7)

HNO3 + NaOH -------> H2O + NaNO3

1:1molar reaction

moles of NaOH consumed = ( 0.300mol/1000ml) × 15.4ml = 0.00462mol

0.00462moles of NaOH react with 0.00462moles of HNO3

moles of HNO3 present in 20.0ml solution = 0.00462mol

concentration of HNO3 = ( 0.00462mol/20.0ml)× 1000ml = 0.231M

8)

2H3PO4 + 3Ca(OH)2 ------> 6H2O + Ca3(PO4)2

stoichiometrically, 2moles of H3PO4 react with 3moles of Ca(OH)2

moles of H3PO4 consumed = ( 1.50mol/1000ml) ×15.65ml = 0.023475mol

0.023475moles of H3PO4 react with 0.035213 moles of Ca(OH)2

moles of Ca(OH)2 present in the 25.00ml solution = 0.035213mol

concentration of Ca(OH)2 = (0.035213mol/25.0ml) ×1000ml = 1.409M

Answer 2

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