Question

Q2. A. Calculate the volume in ml of a 1.72 M Ca(OH), solution required to react with a 250 ml of a 1.8 M H3PO4 solution in anacid-base reaction. (use short-cut technique without balancing) H3PO4(aq) + Ca(OH)2(aq)Ca3(PO.). (aet) + H20 unbalanced B.Calculate the volume of solution required to prepare 2.0 MCa3(PO4)2 by dissolving 62 grams Ca3(PO4)2 in water. Ca=40 0=16 P=31 C. In dilution, what volume of 4.0 M HNO3 (aq) stock (initial) solution is required to prepare a 3.0 liters of 1.5 M HNO3(aq) final solution? What is the volume of pure water added? D.If we mix 1.5 liters of 3 M H2SO4(aq) solution with 2 liters of H2SO4 (aq) solution, what will be the molarity of the final mixture?

Answer 1

Gium 250ml e pou for of 1.8M. no of moles 1.8 x 250 x 10 ox103 =0.45 mde fo 2 nle H₂ pou 43 ml Cacord required. for 0.45 H, H₂Pou 3xo.us mole Cacon), required 20.675 md cacoH), Given molarity of caCOH) = 1.72 M. Volume required a 20.392 L 0.675 1-72 2392mL of caOH), R Molwt of ca, (PO4)2 3x ® 40+ 2x31+ 8x16 - 310 globe 62 =02 mde no of mole of cą (PO4)2 310 CS Scanned with CamScanner

volume required 0.2 - OilL. 2 =100m2 of cas (PO4)2. know @ we Miv,= M₂ V₂ Given Mia UM ; V,-? :M₂ = 281.5 : 4 = 3 4xV;= 1.5x3 V,= 1.125 litre of initial solution required volume of water added added = Ne-v = 3-1-125 = 1.875 Litre of water added 0 Given M, 3M ; vals litre "=2 litre ₂ = ? M. V = M2 V2. 3x1.52 M₂x2, M = 225M - Therefore final molanity of H₂SO4 is 2.25M. CS Scanned with CamScanner

volume required 0.2 - OilL. 2 =100m2 of cas (PO4)2. know @ we Miv,= M₂ V₂ Given Mia UM ; V,-? :M₂ = 281.5 : 4 = 3 4xV;= 1.5x3 V,= 1.125 litre of initial solution required volume of water added added = Ne-v = 3-1-125 = 1.875 Litre of water added 0 Given M, 3M ; vals litre "=2 litre ₂ = ? M. V = M2 V2. 3x1.52 M₂x2, M = 225M - Therefore final molanity of H₂SO4 is 2.25M. CS Scanned with CamScanner