Question 1 : What volume (in mL) of a solution 0.124 M in Ca(OH)2 must we...

Question

Question

Question 1 :
What volume (in mL) of a solution 0.124 M in Ca(OH)₂ must we use to neutralize 25.9 mL of a solution 0.359 M in H₃PO₄.

Answer 1

Answer #1

Ca(OH)2 Ž Ca 2+ + 2011 0-124 m = 0.248M com-] = 2 x 0:12 4 M = 34* + PO43- H₂PO4 0.359m CH+] = 3 x 0.359 M = 1.077M using the

Answer 2

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