Question

006 10.0 points The difference in potential between the accel erating plates of a TV set is about 24 kV. The distance between these plates is 1.2 cm. Find the magnitude of the uniform electric field in this region. Answer in units of N/C
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Answer #1

Solution:

As we know;

∆V =E.d

=> 24000 volts = E (0.012 metres)

=> E = 2 *10^6 volts /metre or Newton/Coulombs (Both S.I units)

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