kindly post different questions separately. please rate
At a certain temperature* (probably not 25 °C), the solubility of silver sulfate, Ag2SO4, is 0.012...
At a certain temperature" (probably not 25 °C), the solubility of silver sulfate, Ag2SO4, is 0.013 mol/L. Calculate its solubility product constant for this temperature. SIG. FIG. (required because number is small) *Solubility product constants are very temperature sensitive. They are generally reported at 25 °C. Not necessarily using this temperature allows me some flexibility, Answer: I
-8 3 Calculate the solubility of copper (10 lodate in 0.15 M copper (1) nitrate, K is 7.4x10M. "You should know that the Kan must refer to the copper lodate because all nitrate compounds are soluble and strong electrolytes Answer: Warm UP Question. What is the initial (before any reaction takes placel lead nitrate concentration when 8.0 mL of 0.111 M lead nitrate is added to 19 mL of 0.0070 M sodium chloride? Answer: K For the reaction: PbCl (s)...
a. At a certain temperature, the solubility of potassium iodate, KIO3, is 36.8 g/L. Calculate its solubility product constant for this temperature. b. At a certain temperature, the solubility of cadmium fluoride, CdF2, is 0.185 mol/L. Calculate its solubility product constant for this temperature. c. At a certain temperature, the solubility product constant* of copper (II) iodate, Cu(IO3)2, is 4.08x10-8 M3. Calculate the solubility of this compound for this temperature.
Solubility product constant Ksp is also important to predict whether the precipitation will occur under the known condition of ion concentration. This can be done by comparing the solubility quotient (Q) with the value of Ksp of the tested compound. 12. A solution of 0.00016 M lead (II) nitrate, or Pb(NO3)2, was poured into 450 mL of 000023 M sodium sulfate, Na2SO4. Would a precipitate of lead(II)sulfate, PbSO4, be expected to form if 250 mL of the lead nitrate solution...
1) For the reaction: PbCl2(s) ↔ Pb2+(aq)+2Cl1-(aq), what is Q* when 2.5 mL of 0.070 M lead nitrate is added to 19 mL of 0.018 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback *Recall: Q is compared to Ksp to determine whether a precipitate forms. 2) Sodium phosphate is added to a solution that contains 0.0041 M aluminum nitrate and 0.028 M calcium chloride. The concentration of the first ion to...
Question 4 At a certain temperature, the solubility product constant of copper in iodate, Cu(los), is 7.17x10M compound for this temperature. Calculate the solubility of this Not yet answered Marked out of 100 "Unless stated otherwise all solubility product constants are for water. F Flag question Answer: 5 Calculate the solubility of copper (1) iodate in 0.40 M copper (11) nitrate, Kupis 74x10M Not you *You should know that the Kp must refer to the copper iodate because all nitrate...
At a certain temperature, the solubility product constant of copper (II) iodate, Cu(O3)2, is 7.17X10 solubility of this compound for this temperature, M. Calculate the "Unless stated otherwise all solubility product constants are for water. Answer:
What is the approximate concentration of free Cu2+ ion at equilibrium when 1.22x102 mol copper(II) nitrate is added to 1.00 L of solution that is 1.210 M in NH3. For [Cu(NH3)4]. Ke-2.1x1013 (Cu?") - Submit Answer Determine ion concentration when separating ions in a mixture. A solution contains 1.58x102 M lead acetate and 1.58x10 ? Mmanganese(II) nitrate. Solid sodium sulfide is added slowly to this mixture. What is the concentration of lead ion when manganese(II)ion begins to precipitate? Solubility product...
Calculate the solubility of barium sulfate. BaSO4 in units of grams per liter. Ksp (BaSO4) = 1.1x10-10 solubility = AL The equilibrium concentration of chloride ion in a saturated lead chloride solution is M. In the presence of excess OH, the Ar+ (aq) ion forms a hydroxide complex ion. Al(OH)4 Calculate the concentration of free Ap+ ion when 1.56x10-mol Al(CH2C00)3(s) is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.10). For Al(OH)4, Ke=...
For the reaction: PbCl2(s) - Pb2+ (aq)+2C1! (aq), what is Q* when 9.0 mL of 0.029 M lead nitrate is added to 15 mL of 0.012 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 Hint given in general feedback * Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer: