1) For the reaction: PbCl2(s) ↔ Pb2+(aq)+2Cl1-(aq), what is Q* when 2.5 mL of 0.070 M...
1) For the reaction: PbCl2(s) ↔
Pb2+(aq)+2Cl1-(aq), what is Q* when 2.5 mL of
0.070 M lead nitrate is added to 19 mL of 0.018 M sodium
chloride?
Ksp of lead chloride is 1.6 x 10-5
M3.
Hint given in general feedback
*Recall: Q is compared to Ksp to determine whether a
precipitate forms.
2) Sodium phosphate is added to a solution that contains 0.0041 M aluminum nitrate and 0.028 M calcium chloride. The concentration of the first ion to precipitate (either Al3+or Ca2+) decreases as its precipitate forms. What is the concentration of this ion when the second ion begins to precipitate?
Homework Answers
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1) For the reaction: PbCl2(s) ↔
Pb2+(aq)+2Cl1-(aq), what is Q* when 2.5 mL of
0.070 M...
For the reaction: PbCl2(s) ↔ Pb2+(aq)+2Cl1-(aq), what is Q* when 1.5 mL of 0.035 M lead nitrate is added to 13 mL of 0.0...
For the reaction: PbCl2(s) ↔ Pb2+(aq)+2Cl1-(aq), what is Q* when 1.5 mL of 0.035 M lead nitrate is added to 13 mL of 0.010 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback *Recall: Q is compared to Ksp to determine whether a precipitate forms.
Pb2+(aq)+2CI1(aq), what is Q* when 9.0 mL of 0.055 M lead nitrate For the reaction: PbCl2(s)...
Pb2+(aq)+2CI1(aq), what is Q* when 9.0 mL of 0.055 M lead nitrate For the reaction: PbCl2(s) is added to 12 mL of 0.028 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback *Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer 0.00577 X
For the reaction: PbCl2(s) Pb2 (aq)+2CI1- (aq), what is Q* when 2.0 mL of 0.051 M...
For the reaction: PbCl2(s) Pb2 (aq)+2CI1- (aq), what is Q* when 2.0 mL of 0.051 M lead nitrate is added to 18 mL of 0.012 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3 Hint given in general feedback Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer:
For the reaction: PbCl2(s) → Pb2+ (aq) + 2Cl(aq), what is Q* when 5.6 ml of...
For the reaction: PbCl2(s) → Pb2+ (aq) + 2Cl(aq), what is Q* when 5.6 ml of 0.043 M lead nitrate is added to 20 ml of 0.022 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback "Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer: Answer:
For the reaction: PbCl2(s) - Pb2+ (aq)+2C1! (aq), what is Q* when 9.0 mL of 0.029...
For the reaction: PbCl2(s) - Pb2+ (aq)+2C1! (aq), what is Q* when 9.0 mL of 0.029 M lead nitrate is added to 15 mL of 0.012 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 Hint given in general feedback * Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer:
At a certain temperature* (probably not 25 °C), the solubility of silver sulfate, Ag2SO4, is 0.012...
At a certain temperature* (probably not 25 °C), the solubility of silver sulfate, Ag2SO4, is 0.012 mol/L. Calculate its solubility product constant for this temperature. SIG. FIG. (required because number is small) Solubility product constants are very temperature sensitive. They are generally reported at 25°C. Not necessarily using this temperature allows me some flexibility. Answer: At a certain temperature, the solubility of potassium iodate, KIO3, is 36.1 g/L. Calculate its solubility product constant for this temperature. Answer: At a certain...
-8 3 Calculate the solubility of copper (10 lodate in 0.15 M copper (1) nitrate, K is 7.4x10M. "You should know tha...
-8 3 Calculate the solubility of copper (10 lodate in 0.15 M copper (1) nitrate, K is 7.4x10M. "You should know that the Kan must refer to the copper lodate because all nitrate compounds are soluble and strong electrolytes Answer: Warm UP Question. What is the initial (before any reaction takes placel lead nitrate concentration when 8.0 mL of 0.111 M lead nitrate is added to 19 mL of 0.0070 M sodium chloride? Answer: K For the reaction: PbCl (s)...
Consider the dissolution equation of lead(II) chloride. PbCl2 (s) Pb2+ (aq) + 2 C1- (aq) Suppose...
Consider the dissolution equation of lead(II) chloride. PbCl2 (s) Pb2+ (aq) + 2 C1- (aq) Suppose you add 0.2331 g of PbCl2(s) to 50.0 mL of water. In the resulting saturated solution, you find that the concentration of Pb2+ (aq) is 0.0159 M and the concentration of Cl - (aq) is 0.0318 M. What is the value of the equilibrium constant, Ksp, for the dissolution of PbCl2? Answer:
What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbCl2 from a solution that is 1.00×10−2 M in...
What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbCl2 from a solution that is 1.00×10−2 M in the chloride ion, Cl−? Ksp for lead(II) chloride is 1.17×10−5
Part A - Calculate the value of Q What is the value of Q when the solution contains 2.00×10?2 M Ca2+ and 3.00×10?2M CrO...
Part A - Calculate the value of Q What is the value of Q when the solution contains 2.00×10?2 M Ca2+ and 3.00×10?2M CrO42?? Express your answer numerically. Part C What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbCl2 from a solution that is 1.00×10?2 M in the chloride ion, Cl?? Ksp for lead(II) chloride is 1.17×10?5 . Express your answer with the appropriate units.
Pb2+(aq)+2CI1(aq), what is Q* when 9.0 mL of 0.055 M lead nitrate For the reaction: PbCl2(s) is added to 12 mL of 0.028 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback *Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer 0.00577 X
For the reaction: PbCl2(s) Pb2 (aq)+2CI1- (aq), what is Q* when 2.0 mL of 0.051 M lead nitrate is added to 18 mL of 0.012 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3 Hint given in general feedback Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer:
For the reaction: PbCl2(s) → Pb2+ (aq) + 2Cl(aq), what is Q* when 5.6 ml of 0.043 M lead nitrate is added to 20 ml of 0.022 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback "Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer: Answer:
For the reaction: PbCl2(s) - Pb2+ (aq)+2C1! (aq), what is Q* when 9.0 mL of 0.029 M lead nitrate is added to 15 mL of 0.012 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 Hint given in general feedback * Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer:
At a certain temperature* (probably not 25 °C), the solubility of silver sulfate, Ag2SO4, is 0.012 mol/L. Calculate its solubility product constant for this temperature. SIG. FIG. (required because number is small) Solubility product constants are very temperature sensitive. They are generally reported at 25°C. Not necessarily using this temperature allows me some flexibility. Answer: At a certain temperature, the solubility of potassium iodate, KIO3, is 36.1 g/L. Calculate its solubility product constant for this temperature. Answer: At a certain...
-8 3 Calculate the solubility of copper (10 lodate in 0.15 M copper (1) nitrate, K is 7.4x10M. "You should know that the Kan must refer to the copper lodate because all nitrate compounds are soluble and strong electrolytes Answer: Warm UP Question. What is the initial (before any reaction takes placel lead nitrate concentration when 8.0 mL of 0.111 M lead nitrate is added to 19 mL of 0.0070 M sodium chloride? Answer: K For the reaction: PbCl (s)...
Consider the dissolution equation of lead(II) chloride. PbCl2 (s) Pb2+ (aq) + 2 C1- (aq) Suppose you add 0.2331 g of PbCl2(s) to 50.0 mL of water. In the resulting saturated solution, you find that the concentration of Pb2+ (aq) is 0.0159 M and the concentration of Cl - (aq) is 0.0318 M. What is the value of the equilibrium constant, Ksp, for the dissolution of PbCl2? Answer:
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