What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbCl2 from a solution that is 1.00×10−2 M in...
What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbCl2 from a solution that is 1.00×10−2 M in the chloride ion, Cl−? Ksp for lead(II) chloride is 1.17×10−5
Homework Answers
For precipitate to form minimum condition is,
[Pb+2][Cl-]^2 = Ksp
[Pb+2] [1x10^-2]^2 = 1.17x10^-5
[Pb+2] = 0.117 Moles/litre
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