Question

A26. What will be observed when 15.0 mL of 0.040 M lead(II) nitrate, Pb(NO3)2, is mixed with 15.0 mL of 0.040 M sodium chloride? (lead chloride Ksp = 1.7 × 10–5).

(A) A clear solution with no precipitate will result.

(B) Solid PbCl2 will precipitate and excess Pb2+ ions will remain in solution.

(C) Solid PbCl2 will precipitate and excess Cl– ions will remain in solution.

(D) Solid PbCl2 will precipitate and there will be no excess ions in solution.

(E) Two solids, PbCl2 and NaNO3, will precipitate

Answer 1

Phol + Znang Pb(NO cap). tenad Coa) and - Compounds containing group & No anno is generally so nang precipitate not Cophon b wrong) cations soluble. form Epbt2) - [Pb(NO ) a males of Pb(Ng? Total volume z oroyom x 15-oml 15-0mL t 15-0ml 2 10-ozom (T) (Nach) moles of Nach Total volume 0.04om x 15-oml 30-ome 20-ozom - obges y 2 pbth Po cool +201 coal Solubility product Home Q. 2 (obt2) [W? se - 2 [0.020) Co.0oot 8.0x10r. here Is < Isp , so no precipitale form, as the [Pbt 2) and (ar) product is less than equlibrin concenhotion. so all pbt2 & ci are present as ons and not pbchod A. So A Answer clear as sowron olh no precipitate lll result