If 26 moles of NO combine with 42 moles of H,, how many moles of NH,...

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If 26 moles of NO combine with 42 moles of H,, how many moles of NH, can form? What is the limiting reagent? 2 NO(g) + 5 H2(g

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2 N00g) + 5H2(g) + 2NH3 4) + 2H2009) By soen, 5 mol H₂ react with = amol No 242 mol he react with a (3 x 42) mol No = 16.8 mo Stepl: 26 moles Nox pmoles NH3 @G moles) NH3 - 2 moles No 42 moles H₂ x 2 moles NH3 = 116.8 moles/ NH3 Step2: Limiting reacta

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If 26 moles of NO combine with 42 moles of H,, how many moles of NH,...

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