Question

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If 66 moles of NaOH combine with 26 moles of H, PO,, how many moles of H, O can form? What is the limiting reagent? 3 NaOH(aq) + H, PO, (aq) — 3H,O(1) + Na, PO, (aq) Step 1: Find the number of moles of H, each starting material could form. 66 moles NaOH X 66 moles H₂o 26 moles H, PO, 3 moles H,0 1 mole H, PO 18 moles H₂o Answer Bank 3 moles NaOH 1 mole H, PO 3 moles H, 1 mole Na, PO. Step 2: Determine the limiting reagent. O NaOH OH, PO

Answer 1

NaOH(aq) + H₂ Poulag) 3H2O(l) + Na, Pou (aq) that I mole af H₂PO4 from the reaction we can see I require 3 moles of NaOH Imole of H₂ pou require 3 mole of NaOH 26 mole of H₂ pou require se mole of NaOH - l = 3 26 e a= 26x3 = 78 moles 1 78 moles required to react Completely with 26moles I el H₂ pou but only 66 moles of NaOH is present Il nenu naoh here is chimicting reagent because it is in limited amount & it decide the amount of product form. I from the reaction we can see 3 moles cef NaoH produce a moles cy H₂O 3 moles of NaOH produce 3moles of H₂O 16689 moles of Naoh produce se moles of H₂O in moles of H₂O 5 = 3 6698 e - 8x3 - 9 mole hence 88 moles el NaOH produce 66 moles of H₂O