Molar mass of Co(OH)2,
MM = 1*MM(Co) + 2*MM(O) + 2*MM(H)
= 1*58.93 + 2*16.0 + 2*1.008
= 92.946 g/mol
Molar mass of Co(OH)2= 92.946 g/mol
s = 0.16 g/L
To covert it to mol/L, divide it by molar mass
s = 0.16 g/L / 92.946 g/mol
s = 1.721*10^-3 mol/L
At equilibrium:
Co(OH)2 <----> Co2+ + 2 OH-
s 2s
Ksp = [Co2+][OH-]^2
Ksp = (s)*(2s)^2
Ksp = 4(s)^3
Ksp = 4(1.721*10^-3)^3
Ksp = 2.04*10^-8
Answer: 2.0*10^-8
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