probability of getting 5 = 1/6
X = number of time fives occur
X follow N (np , np*q)
here n = 200
N(200*1/6 , 200*1/6*5/6) = N ( 33.333333 , 27.7777777778 )
=P(X <= 30)
= P(X <= 30.5)
= P(Z < ( 30.5 - 33.333333)/ sqrt(27.7777777778))
= P(Z < -0.537587 )
= 0.2954
option B) is correct
Help please ! 3 complete)D This Test: 40 pts Find the probability that in 200 tosses...
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