A 75.0-ml. sample of 0.0650 MHCN (K -62 x 10-19) is titrated with 065 M NaOH....

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Answer 1

Answer #1

No. of Moles of HON= Molariety x reoleme of Solution (in liten . Moles of HON=0.065x75x103 = 4.875x103 Let volume of NaOH req

Answer 2

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