Question

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Air N Linseed oil 10. Write down two conditions for total internal reflection. The figure shows a refracted light beam in linseed oil making an angle of $ = 30.6° with the normal line NN'. The index of refraction of linseed oil is 1.48. (Refractive index of water -1.33, Refractive index of air=1). Calculate following. (2+2+2+2). (a) Determine the angle 0. Water - >

Answer 1

Sol - From Question we have air - Tot ail he water Refractive index of oil = 1.48 = Moil Refractive index of water=1.33 - Mw Refractive index of air = 1 = Mair Two condition for Total internal Reflection = 1. Light must travel from denser medium to rare medium. 2. Angle of incidence must be greater than critical angle a = We have 6=30.6° Since we know Shell's law Mair sin 0 = Morbind Suno=1.48 Sin (30.6) o=48.87° Hence o = 48.87° B: For ail and water interface Moil Sin (30.6) = Mo Sin Col 1.48 Sun (30.6) = Sin (0) 1.33 0' - 34,49° - critical angle for oil-water interface Let this critical angle is Oc. Oc is angle of incidence for all interface So we have Sinoc = Uw = 4:33 - Mail 1.48 Oc=63.970 Hence critical angle o c= 63.970