Relative speed of the Frank's van u=30-1= 29 m/s
Distance travel during deceleration d=150 m
The speed of the ven when collision occurred v=5 m/s
Since Deceleration is a constant rate means deceleration is constant. So
Using equation of the motion
v^2=u^2-2ad
a=u^2-v^2 /2d
a=29^2-5^2/(2×150)
a=(841-25)/(300)
a=2.72 m/s^2. Answer
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