Question

Review VPartA A parallel-plate capacitor is made from two aluminum-foil sheets, each 6.3 cm wide and 6.0 m long. Between the sheets is a Teflon strip of the same width and length that is 4.5x10-2 mm thick. What is the capacitance of this capacitor? (The dielectric constant of Teflon is 2.1.) Express your answer using two significant figures. Submit Request Answer

Answer 1

Area

A=0.063*6 =0.378 m²

Capacitance of the capacitor is given by

$C=\frac{K\varepsilon _{o}A}{d}=\frac{2.1\times 8.8542\times 10^{-12}\times 0.378}{(4.5\times 10^{-2}\times 10^{-3})}$

C=1.56*10^-7 F =0.156 uF

C=0.16 uF (approx up to 2 significant figures)