what is the molar solubility of AgBr in 0.10M FeBr3? Ksp(AgBr)= 5.010^-13 a. 3.910^-14M b. 1.7*10^-12M...

Question

Question

what is the molar solubility of AgBr in 0.10M FeBr3? Ksp(AgBr)= 5.0*10^-13

a. 3.9*10^-14M

b. 1.7*10^-12M

c. 1.9*10^-11M

d. 2.7*10^-10M

e. 6.2*10^-12M

Answer 1

Answer #1

Given,

K_sp of AgBr = 5.0 x 10^-13

Concentration of FeBr₃ = 0.10 M and after dissociation concentration of Br^- becomes 0.30 M.

Solubility of AgBr will be equals to [Ag⁺].

Ag+ = Ksp - 5.0 x 10-13 Ag+ - Br-1= 0.3

Ag+ = 16.6 x 10-13 = 1.7 x 10-12M

Option b is correct.

Answer 2

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what is the molar solubility of AgBr in 0.10M FeBr3? Ksp(AgBr)= 5.0*10^-13 a. 3.9*10^-14M b. 1.7*10^-12M...