Question

A diverging lens with a focal length of -19.8 cm and a converging lens with a focal length of 17.9 cm have a common central axis. Their separation is 37.3 cm. An object of height 1.0 cm is 28.2 cm in front of the diverging lens, on the common central axis. Find the location of the final image produced by the combination of the two lenses. Where is the image located as measured from the converging lens? Submit Answer Tries 0/10 What is the height of that image? Submit Answer Tries 0/10 With respect to the original object, is the image is real or virtual, upright or inverted? Check all statements that are true. Select all that are True. The image is inverted The image is real The image is virtual The image is upright Submit Anmor Tries 0110

Answer 1

Salton Object Taroum 982 37.3 cm focal length of diverging lens – 19.8 cm a focal length of converging lens - 17.9 cm lens formula - - t - 7 V u of image distonie object distonie to cal length for diverging lens M. - 28.2 cm 19.8 cm

2.2 19.8 - 198 282 V = -11 63 cm hence the distonice this image from the converging lens which act as object for this lens M – 11.63+ (-37.3). - 48.93 cm te - (719cm t t => 148.93 - 4 &193 TV- 28 .22 cm image distonce from converging lensis 29.22 cm magnificention Image height image distonie object height object distance

he h = 28:22 48.93 Thu 058 cm image in real & inverted.