Question

A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual

Answer 1

using lens formula for converging lens

1/f = 1/v - 1/u

1/8.2 = 1/ v + 1/4.85

v = 11.87 cm

now the above image acts as kbject for diverging lens

object distance of which is given by

u' = 11.87 + 6 = 17.87

using lens formula for diverging

- 1/16 = 1/ v' + 1/17.87

v' = 8.442 cm

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image is virtual and upright