A converging lens of focal length 20.0 cm is separated by 50.0 cm from a converging...
A converging lens of focal length 20.0 cm is separated by 50.0
cm from a converging lens of focal length 5.00 cm.
a) Find the position of the final image of an object placed 42.0 cm
in front of the first lens. Solve graphically and
mathematically.
b) If the height of the object is 2.00 cm, what is the height of
the final image?
c) Is the final image real or virtual? Is it inverted or
upright?
Homework Answers
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A converging lens of focal length 20.0 cm is separated by 50.0
cm from a converging...
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal...
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual
A diverging lens of focal length –30.0 cm is placed 25.0 cm behind a converging lens...
A diverging lens of focal length –30.0 cm is placed 25.0 cm behind a converging lens of focal length 60.0 cm. A real, upright object of height 2.00 cm is placed 20.0 cm in front of the converging lens. (a) Determine the location of the final image. (Clearly state the location of the final image.) (b) Determine the size and the nature of the final image.
A diverging lens with a focal length of -19.8 cm and a converging lens with a...
A diverging lens with a focal length of -19.8 cm and a converging lens with a focal length of 17.9 cm have a common central axis. Their separation is 37.3 cm. An object of height 1.0 cm is 28.2 cm in front of the diverging lens, on the common central axis. Find the location of the final image produced by the combination of the two lenses. Where is the image located as measured from the converging lens? Submit Answer Tries...
12) A converging lens with a focal length of 10 cm is separated by 30 cm...
12) A converging lens with a focal length of 10 cm is separated by 30 cm from a diverging lens with a focal length of 8 cm. An object is placed 20 cm in front of the converging lens as shown below. What is the final position and orientation of the image formed by this two-lens system? A. Upright, 10.0 cm to the left of the diverging lens. B. Inverted, 6.0 cm to the left of the diverging lens. C....
A 5.00-cm tall candle is placed 50.0 cm to the left of a thin converging lens...
A 5.00-cm tall candle is placed 50.0 cm to the left of a thin converging lens that has a focal length of 15.0 cm. To the right of the lens, 30.0cm away, another converging lens (focal length 20.0cm) is placed. Determine type (real/virtual), orientation (upright/inverted), location (with respect to the second lens) and height of the final image formed by the light as it passes through both lenses.
A 5.00-cm tall candle is placed 50.0 cm to the left of a thin converging lens...
A 5.00-cm tall candle is placed 50.0 cm to the left of a thin converging lens that has a focal length of 15.0 cm. To the right of the lens, 30.0cm away, another converging lens (focal length 20.0cm) is placed. Determine type (real/virtual), orientation (upright/inverted), location (with respect to the second lens) and height of the final image formed by the light as it passes through both lenses.
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length o...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
Two converging lenses, each having a focal length equal to 11.0 cm, are separated by 36...
Two converging lenses, each having a focal length equal to 11.0 cm, are separated by 36 cm. An object is 22 cm to the left of the first lens. a) Findthe position of the final image using both a ray diagram and the thin-lens equation. cm to the right of the object (b) Is the final image real or virtual? O real O virtual Is the final image upright or inverted? O upright O inverted (c) What is the overall...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the left of a diverging lens having a focal length of -11.0 cm. If an object is located 9.9 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. a) Where is the image located as measured from the diverging lens? b) What is the magnification? c) Also determine, with respect to the original object...
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual
A diverging lens with a focal length of -19.8 cm and a converging lens with a focal length of 17.9 cm have a common central axis. Their separation is 37.3 cm. An object of height 1.0 cm is 28.2 cm in front of the diverging lens, on the common central axis. Find the location of the final image produced by the combination of the two lenses. Where is the image located as measured from the converging lens? Submit Answer Tries...
12) A converging lens with a focal length of 10 cm is separated by 30 cm from a diverging lens with a focal length of 8 cm. An object is placed 20 cm in front of the converging lens as shown below. What is the final position and orientation of the image formed by this two-lens system? A. Upright, 10.0 cm to the left of the diverging lens. B. Inverted, 6.0 cm to the left of the diverging lens. C....
A 5.00-cm tall candle is placed 50.0 cm to the left of a thin converging lens that has a focal length of 15.0 cm. To the right of the lens, 30.0cm away, another converging lens (focal length 20.0cm) is placed. Determine type (real/virtual), orientation (upright/inverted), location (with respect to the second lens) and height of the final image formed by the light as it passes through both lenses.
A 5.00-cm tall candle is placed 50.0 cm to the left of a thin converging lens that has a focal length of 15.0 cm. To the right of the lens, 30.0cm away, another converging lens (focal length 20.0cm) is placed. Determine type (real/virtual), orientation (upright/inverted), location (with respect to the second lens) and height of the final image formed by the light as it passes through both lenses.
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
Two converging lenses, each having a focal length equal to 11.0 cm, are separated by 36 cm. An object is 22 cm to the left of the first lens. a) Findthe position of the final image using both a ray diagram and the thin-lens equation. cm to the right of the object (b) Is the final image real or virtual? O real O virtual Is the final image upright or inverted? O upright O inverted (c) What is the overall...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
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