Question

A 5.00-cm tall candle is placed 50.0 cm to the left of a thin converging lens that has a focal length of 15.0 cm. To the right of the lens, 30.0cm away, another converging lens (focal length 20.0cm) is placed. Determine type (real/virtual), orientation (upright/inverted), location (with respect to the second lens) and height of the final image formed by the light as it passes through both lenses.

Answer 1

li رل ni som by michael SON -V -V2 30cm - u fi= 15cm u = som harum Using f • ry 50x15 Sx15 50 45 35 Vi = 21-43cm + so is U2 = V-30 --8-57cm fz=200m + 81- V2 8-57 20857 Y V2 -15cm 8-01-20 hi Vaj ay his sx-0.429 ij hi hi--2-14cm h2 - hi'2-2014cm nilha Valur 3-2.14 x 1•15 =-3.75cm

vioheal image ܓ For the second lene image & object on same side 180 verhial since ha' is-ve the image is inverted to V₂ is -ve which implice image is to the left of sewna lene 12'<h, so the final image is diminished ha's -3.75 cm O