Question

Suppose f (x)=x+ (x - 1). Then f (x) = x (3x - 2). Over which interval(s) is the graph off both increasing and concave up?


Suppose f(x) = x+ (x - 1). Then f(x) = x (3x - 2). Over which interval(s) is the graph off both increasing and concave up?
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Answer #1

f is both increasing and concave up if x>1 . Lets see how.

Please refer to the below picture.

C)= (3x-2) i imrcavin ake foo Henu m the imtue of ,) fo is imcrean 1s Concane up if fC)0, (3-2) 70 tenu o(x-2)0 m th intava

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