Question

Part 2 (0.3 point) How much chalcopyrite had to be mined to produce 100 pennies if reaction 1 had a percent yield of 65.00 % and all other reaction steps had yield of 100%? g CuFeS2 Part 3 (0.3 point) How much chalcopyrite had be mined to produce 100 pennies if each reaction involving copper proceeded in 65.00 % yield? g CuFeS2

Answer 1

i 2 CuFeS₂ + 30, 2cus + 2FeO + 250₂ 2 FeO + 2SiO2 • 2fesio, 2 cus Custs iv) cus + s + 20₂ - 200 + 250₂ Port - 1 one penny = 39 of Cu 100 pennies = 300 g cu :. moles of Cu = 300 63.5 Let the moles of cures, had to be mined for 100 pennies = x x moles of Cures, will produce a mole cus (from eq i)) x mole of Cus will produces a mole Cu₂s and & mole of Cugs will produce = 2x2 mol. a = κ ηδle Cυ x= 300 mole 63.5 mole mass of CuFeS₂ = xx Molecular wt. of Cutes = 300 x 183.5 63.5 = 866.9 g

Part - 2 " reaction i had a percent yield = 65% . if we start with the more of Cures, 0.65 x mole of cus will form 0.65 n mole of cus will form 0.654 mole cus 1.650 mole of Curs will form 0.65 x mole cu 2 272 0.65 x = 300 63.5 x= 300 63.5 x 0.65 i mass of X 183.5 CuFeS₂ = 300 x = 1333.7 g 1 333.7 Part 3 x mote 0.65n " Cufes, will Cus " form " 0.65 n mole cus 0.65% 0.65 n mol cus - 2 2 x 0.65 Cu 0.65% 0.65 n cus " 0.65% 0.65% mole 0.65% 0.65% 0.65 x = 300 63.5 CuFeS = mass of 300 x 183.5 63.5x0.650.650.65 - 3156.8 g