Question

Plzz answer and show all work for the questions below. Including any Free body diagrams.

A 0.50 kg ball is attached to al and the entially ch, the ball is at point A (with the rod horizontal) 2.00 m/s: The ball has an internal thruster s attached to a light rod of radius R (-1.20m). When the experimenter starts her stonwatch the ball is at point A and the ball is moving with speedy. 2.00 m/s: The ball has an acting tangentially which causes an angu gentially which causes an angular acceleration of 0.100 rad/s. The ball m es to accelerate around the circle passing through Point A 2 times after the of the stopwatch it started at Point A and then passed through that same point two more time w more times). After that last time through Point A. the ball continues on until it reaches Point B where the glue holding the ball to the rod fails and the ball is launched. Point B lies 35° below the horizontal (that is, - 35°). around of Portone 110 launches Point B w After that last tirPoint A and then push. Po 26. Find the speed of the hall iust as it is launched from Point B. 23.04 m's b. 4.11 m/s c. 2.51 m's d. 6.92 m's 21. Find the tension in the rod just before the ball is released from Point B. a. 21.1 N b. 2.44 N c. 13.2 N d. 6.67 N 28. Find the radial acceleration iust before the ball is launched from Point B. a. 7.71 m/ s b . 3.04 m/s c. 15.2 m/s d. 0.120 m/s2 29. Find the tangential acceleration just before the ball is launched from Point B. b. 3.04 m/s c. 15.2 m/s2 d. 0.120 m/s 30. Find Hmax (as defined in the diagram). a. 3.22 m b. 5.12 m C. 0.600 m d . 2.63 m 31. Find Rx (as defined in the diagram). a. 2.70 m b . 4.32 m c. 1.03 m d . 8.25 m Work space for Question V. (be sure to identify each number's work):

Answer 1

Problem can be solve as below, ( ans of first 4 question as per guideline.)

AMS- m=0.5kg R = 1. 2m Vo = 2.oomis S- wo - Ř - 5 rad/s 31.6, a=0.1 rad/s2 = 35' Hamax - Rx Before B point bull complete tot el 209+25+ 360+360+ (360-35) o 1045 deg. 5.806 god - w?-wp² = 20e = 18.2 4 rad + 2 * 0.1 X 18.24 WWtot * 18.24 W = 2.535 zadel Now Verw V - 1.24 2.535 IN= 3,042 m/s) Ans. 126] Ta my? 0.5% 3.0422 1.2 + 0.5*9.91 X COS 55 155> Fcrmgsins = 16,67 N Ans[27] ara evi - (7.41 M/S2] Ams by apark - 1.240.1 -0.12 m/s2] Ans la