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A copper block with a mass of 600 grams is cooled to 77K by being immersed...

A copper block with a mass of 600 grams is cooled to 77K by being immersed in liquid nitrogen. The block is then placed in a Styrofoam cup containing some water that is initially at +50.0°C. Assume no heat is transferred to the cup or the surroundings. The specific heat of liquid water is 4186 J/(kg °C), of solid water is 2060 J/(kg °C), and of copper is 385 J/(kg °C). The latent heat of fusion of water is 3.35 x 10^5 J/kg. What is the mass of water in the cup, if the final temperature is -30.0°C? _______ grams

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Answer #1

Here,

let the mass of water in the cup is m

heat lost by water = heat gain by the copper block

m *(4.186 * 50 + 334 + 2.06 * 30) = 600 * 0.385 * (243 - 77)

solving for m

m = 63.4 gm

the mass of water in the cup is 63.4 gm

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