Question

right. The probability that each device functions is 95%. All devices have the same probability on w not other devices are functional. What is the probability that the circuit operates? Round or your final answer to the nearest thousandth.

Answer 1

There are three circuits broader circuits (A,B,C,D,E,F) & (G) and (H,I) through which if the current passes only then the current pass from left to right.

The 1st circuit has 3 branches which are in parallel, and if the current passes through any of the branches, it will pass to the other end, to the 2nd Circuit

Probability of Current passing through A,B = 0.95*.95= .9025

Probability of Current passing through C,D,E= 0.95*.95.95=0.85375

Probability of Current passing through F= 0.95

Probabilty that Current passes though any of these branches is equal = 1/3

So probability that current passes end to end through circuit 1 = $\frac{\left(.9025+.85375+.95\right)}{3}=$ $0.90208\dots$

Probabiliy that Current passes through G= .95

Probabiliy that Current passes through H,I= $\frac{\left(.95+.95\right)}{2}=$ 0.95

Hence the total probability of Current passing ernd to end through3 circuits = .95*.95*.90208=.818