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10. Benzylamine is a weak base. The pK, of benzylammonium ion is 9.35. Calculate the pH of a 1.75 x 10-3 M solution of benzyl
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Answer #1

Pka ( benzylammonium ion ) + Pkb ( Benzylamine ) = 14 ( relation is true for conjugate acid - base pair )

Pkb ( benzlyamine ) = 14 — 9.35 = 4.65

Kb ( Benzylamine ) = 10-Pkb   = 10–4.65 = 2.24x 10–5

pH calculation

CH, CH₂ NH₃ + H₂O =(HCMNH, TOH 1.75 Xio -X ta ta. 15x103_n) fata -5 - 3 -4 Kis x?_ = 2.24xió (175x10 cry solving this x = 1.8

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