Homework Answers
mmoles of HCOOH = 50.5 x 0.5300 = 26.8
mmoles of KOH = 0.2900 x 101 = 29.29
[OH-] left = 29.29 - 26.8 / (50.5 + 101 )
= 0.0164 M
pOH = -log [OH-]
= 1.78
pH + pOH = 14
pH = 12.22
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