Homework Answers
millimoles of butanoic acid = 60.1 x 0.5200 = 31.252
millimoles of KOH = 18.7 x 1 = 18.7
HA + KOH --------------> A- + H2O
31.252 18.7 0 0
12.552 0 18.7
pH = pKa + log [salt / acid]
= 4.82 + log [18.7 / 12.552]
pH = 4.99
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