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Previous Page Next Page Page 8 of 9 Question 8 (2 points) Dole Pineapple Inc. is concerned that the 450 mL can of sliced pineapple is being overfilled. The population standard deviation is 0.85 mL. The quality control department took a random sample of 50 cans and found that the arithmetic mean volume was 451.4 mL. At the 5% level of significance, can we conclude that the mean volume is greater than 450 mL? The decision is to not reject Ho. The cans are not being overfilled The decision is to reject Ho. The cans are being overfilled The decision is to reject H1. The cans are being underfilled. The decision is to reject Ho. The cans are not being overfilled. They contain 450mL or less. The decision is to reject H1. The cans are being overfilled

math   Statistics-And-Probability   
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Answer. - Date: -21/01/2019 z - test We have to perform right-tail hypothesis test Step1 Dole Pineapple Inc. is concemed that the 450 mL can of sliced pineapple is being overfilled The population standard deviation is σ= 0.85 mL The null and alternative hypotheses are Ho : μ-450 (The population mean is μ-450) H1 : μ > 450 (The population mean is greater than μ-450) Step 2. The sample size is n = 50, We decide to use α = 0.05 Step3 The table value of the z-test stati stic is zoos.645 Reject Ho if Z >1.645 otherwise do not reject Ho Step4 Using n = 50, 1-45 1.4mL, σ= 0.85ml. The formula for calculating the z-test stati stic is 451.4-450 0.85 50 14 0.85 7.071068 0.120208 = 1164646 Zo 11.64646 Step5 Pyalue = P(z > z0) -1-P(zSzo = 1-P(zs11.65) P-value = 0.000 Conclusion Since the P-value 0.000 < α= 0.05. We reject Ho Since the test statistic is z= 11.65 zoos = 1.645, we reject the null hypothesis There is suffici ent evi dence to conclude that the populati on mean is greater than 450mL.

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