Homework Answers
a)as disease is very rare ; therefore conditional probability that the person have the disease given tested positive will be very less.Therefore this is a good news,
b)
P(tested positive)=P(have disease and tested positive)+P(not have disease and tested positive)
=(1/10000)*0.99+(1-1/10000)*(1-0.99)=0.010098
hence P(have the disease given tested positive)
=P(have disease and tested positive)/P(tested positive)=(1/10000)*0.99/0.010098=0.009804
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