Question

can someone solve c)

Problem 3: Newton's third law An apple of mass 0.1 kg falls from a tree to the ground 2.0m below. a) How long does it take the apple to hit the ground? b) During the fall, what magnitude of force does the apple exert on the Earth? c) Approximately how far does the Earth move towards the apple during the fall? d) During the fall, is the apple moving, the Earth moving, or both, or neither? Explain your answer.

Answer 1

- ② Given, m = 0.1kg I m Apple h=2.0m fi AF Ground f = force exested on apple due to earth (ground) - f = mg, where. g = acceleration due to gravity f = 0.189.81 = F = 0.981N According to Newton's third law of motion- F = F2 In A - F2 = Me x ge where, Me= mass of earth = 5.972x1024 kg ge = acceleration of earth due to apple. Je = £2 = 0.981 = 0.164x1024 m/s2 de Me 5.972x102 t = Using time taken by the apple to fall to ground. equation of motion- Now 2 = 12 x 9.81 x+2 t = 0.638 seconds) distance travelled by the ground towards the apple during this time interval- S = 1 get² S = -x 0.164x1524 x(0.638)2 S = 3-34 x 10 m