What mass of precipitute is formed when 125 ml of 200 M BaCl2 und 35 ml...

Question

Question

Answer 1

Answer #1

0.2007 Millimoles of Bach = 25.00 x - 5 . . Na₂SO4 = 35.00 x 0.125 = 4.375 C will react with 4.375 moles of Ball (Acc. to the

Answer 2

Similar Homework Help Questions

What mass of precipitute is formed when 125 mL OF »200 M BaCl2 und 35ml of...

What mass of precipitute is formed when 125 mL OF »200 M BaCl2 und 35ml of 0.125 M Na SO4 are mixed? given: 25.00mL of 200M Buclz 35.00mL of .125 M Na, 504 molanty:. 200 M Bach, 0.125M Nazsoy
What is the mass of the precipitate that forms when 50 mL of 0.3 M BaCl2...

What is the mass of the precipitate that forms when 50 mL of 0.3 M BaCl2 reacts with 45 mL of 0.35 M Na2CO3?
b. When 12.00 mL of 0.183 M BaCl2 were mixed with 10.00 mL of 0.352 M...

b. When 12.00 mL of 0.183 M BaCl2 were mixed with 10.00 mL of 0.352 M of Na2C2O4, a student collected 0.108 g of precipitate. Calculate: Mole of BaCl2 Precipitating Calcium Carbonate CHM121 General Chemistry Lab I Mole of Na2C204 H.Y. & S.D. Identify the limiting reagent Mole of BaC204 Mass (g) of BaC204 Percent yield of BaC204

What mass of Ag2CO3 is formed when 25.0-mL of 0.200-M AgNO3 are mixed with 50.0-mL of...

What mass of Ag2CO3 is formed when 25.0-mL of 0.200-M AgNO3 are mixed with 50.0-mL of 0.0800-M Na2CO3? Na2CO3 (aq) + 2AgNO3 (aq) ⟶⟶ Ag2CO3(s) + 2NaNO3(aq)
if 25.26 mL of a 0.125 M solution of aluminum hydroxide reacts exactly with 22.00 mL of a sulfuric acid solution, what...

if 25.26 mL of a 0.125 M solution of aluminum hydroxide reacts exactly with 22.00 mL of a sulfuric acid solution, what is the molarity of the sulfuric acid solution? 3H2SO4(aq) + 2Al(OH)3(aq) → Al2(SO4)3(aq) + 6H20(1) a) How many grams of aluminum hydroxide will react with 75,0 mL of 0.319 M sulfuric acid solution? moles of H₂SO4 0.3198 0.075 0.0239 moles 3 moles of H2Soy requires 2 moles Al(OH)3 0.023a moles of the 504 - 2xo.0239 moles of Al(OH)₃...
What mass of barium sulfate (233 g/mol) is produced when 125 mL of a 0.150 M...

What mass of barium sulfate (233 g/mol) is produced when 125 mL of a 0.150 M solution of barium chloride is mixed with 25 mL of a 0.175 M solution of iron(III) sulfate

375 mL of a 0.150 M aqueous solution of silver (I) nitrate is mixed with 125...

375 mL of a 0.150 M aqueous solution of silver (I) nitrate is mixed with 125 mL of a 0.125 M aqueous solution of sodium phosphate. Calculate the mass of precipitate that forms and the final concentration of each ion in the mixed solution. Volumes are additive and the precipitation reaction goes to completion. Can you show all work for calculating the final concentration of each ion in the reaction including Ag, NO3^-1, Na and PO4^-3
find the mass of barium sulfate formed when 30. mL of 0.2 M barium nitrate is...

find the mass of barium sulfate formed when 30. mL of 0.2 M barium nitrate is mixed with 100 mL of 0.04 M sodium sulfate
Calculate the mass of precipitate formed when 340. mL of 2.53 M solution of K3PO4 is...

Calculate the mass of precipitate formed when 340. mL of 2.53 M solution of K3PO4 is mixed with 360. mL of 2.75 M solution of Pb(NO3)2. 2 K3PO4 (aq) + 3 Pb(NO3)2(aq) - Pb3(PO4)2 (s) + 6NaNO3 (aq)

0.125M 8) What mass of iron (III) hydroxide precipitate can be pr Fe(NO3)3 with 125 ml 0.150 M NaOH? (45 pts) The n...

0.125M 8) What mass of iron (III) hydroxide precipitate can be pr Fe(NO3)3 with 125 ml 0.150 M NaOH? (45 pts) The net ionic reactions Fe3+ 3 OH 3 0.150 M be produced by reacting 75.0 ml of 0.105 M Fe(OH)34)